Two capacitors of capacitance 3mu F and 6mu F are charged to a potential of 12V each. They are now connected to each other with the positive plate ...
After positive and negative plates of both capacitors joined together. then, Q n e t = 36 μ C (72 − 36 μ F) and C n e t = (3 + 6) μ F ∴ or V = Q C V = 36 μ C 9 μ F or V = 4 V Was this answer helpful? 66 Similar Questions Q1 Two capacitors of capacitance 3 μ F 6 ...